x^2-4x-4.5=0

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Solution for x^2-4x-4.5=0 equation: 



x^2-4x-4.5=0

a = 1; b = -4; c = -4.5;
Δ = b2-4ac
Δ = -42-4·1·(-4.5)
Δ = 34
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{34}}{2*1}=\frac{4-\sqrt{34}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{34}}{2*1}=\frac{4+\sqrt{34}}{2}
$

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